# 泊松比

${\displaystyle G={\frac {E}{2(1+\nu )}}}$

## 參考資料

1. ^ Nana Ho. 柚子帽是真的！BMW 參考柚子皮結構做防護配件，保護性能提升 20%. 科技新報. 2017-10-04 [2019-08-08]. （原始内容存档于2019-08-07）.

## 相關條目

${\displaystyle (\lambda ,\,G)}$ ${\displaystyle (E,\,G)}$ ${\displaystyle (K,\,\lambda )}$ ${\displaystyle (K,\,G)}$ ${\displaystyle (\lambda ,\,\nu )}$ ${\displaystyle (G,\,\nu )}$ ${\displaystyle (E,\,\nu )}$ ${\displaystyle (K,\,\nu )}$ ${\displaystyle (K,\,E)}$ ${\displaystyle (M,\,G)}$
${\displaystyle K=\,}$ ${\displaystyle \lambda +{\tfrac {2G}{3}}}$ ${\displaystyle {\tfrac {EG}{3(3G-E)}}}$ ${\displaystyle {\tfrac {\lambda (1+\nu )}{3\nu }}}$ ${\displaystyle {\tfrac {2G(1+\nu )}{3(1-2\nu )}}}$ ${\displaystyle {\tfrac {E}{3(1-2\nu )}}}$ ${\displaystyle M-{\tfrac {4G}{3}}}$
${\displaystyle E=\,}$ ${\displaystyle {\tfrac {G(3\lambda +2G)}{\lambda +G}}}$ ${\displaystyle {\tfrac {9K(K-\lambda )}{3K-\lambda }}}$ ${\displaystyle {\tfrac {9KG}{3K+G}}}$ ${\displaystyle {\tfrac {\lambda (1+\nu )(1-2\nu )}{\nu }}}$ ${\displaystyle 2G(1+\nu )\,}$ ${\displaystyle 3K(1-2\nu )\,}$ ${\displaystyle {\tfrac {G(3M-4G)}{M-G}}}$
${\displaystyle \lambda =\,}$ ${\displaystyle {\tfrac {G(E-2G)}{3G-E}}}$ ${\displaystyle K-{\tfrac {2G}{3}}}$ ${\displaystyle {\tfrac {2G\nu }{1-2\nu }}}$ ${\displaystyle {\tfrac {E\nu }{(1+\nu )(1-2\nu )}}}$ ${\displaystyle {\tfrac {3K\nu }{1+\nu }}}$ ${\displaystyle {\tfrac {3K(3K-E)}{9K-E}}}$ ${\displaystyle M-2G\,}$
${\displaystyle G=\,}$ ${\displaystyle {\tfrac {3(K-\lambda )}{2}}}$ ${\displaystyle {\tfrac {\lambda (1-2\nu )}{2\nu }}}$ ${\displaystyle {\tfrac {E}{2(1+\nu )}}}$ ${\displaystyle {\tfrac {3K(1-2\nu )}{2(1+\nu )}}}$ ${\displaystyle {\tfrac {3KE}{9K-E}}}$
${\displaystyle \nu =\,}$ ${\displaystyle {\tfrac {\lambda }{2(\lambda +G)}}}$ ${\displaystyle {\tfrac {E}{2G}}-1}$ ${\displaystyle {\tfrac {\lambda }{3K-\lambda }}}$ ${\displaystyle {\tfrac {3K-2G}{2(3K+G)}}}$ ${\displaystyle {\tfrac {3K-E}{6K}}}$ ${\displaystyle {\tfrac {M-2G}{2M-2G}}}$
${\displaystyle M=\,}$ ${\displaystyle \lambda +2G\,}$ ${\displaystyle {\tfrac {G(4G-E)}{3G-E}}}$ ${\displaystyle 3K-2\lambda \,}$ ${\displaystyle K+{\tfrac {4G}{3}}}$ ${\displaystyle {\tfrac {\lambda (1-\nu )}{\nu }}}$ ${\displaystyle {\tfrac {2G(1-\nu )}{1-2\nu }}}$ ${\displaystyle {\tfrac {E(1-\nu )}{(1+\nu )(1-2\nu )}}}$ ${\displaystyle {\tfrac {3K(1-\nu )}{1+\nu }}}$ ${\displaystyle {\tfrac {3K(3K+E)}{9K-E}}}$